7x^2-15x-32=0

Solution for 7x^2-15x-32=0 equation:

7x^2-15x-32=0

a = 7; b = -15; c = -32;
Δ = b2-4ac
Δ = -152-4·7·(-32)
Δ = 1121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1121}}{2*7}=\frac{15-\sqrt{1121}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1121}}{2*7}=\frac{15+\sqrt{1121}}{14}
$